(x^2+x-1)(x+1)=0

Solution for (x^2+x-1)(x+1)=0 equation:

Simplifying
(x2 + x + -1)(x + 1) = 0

Reorder the terms:
(-1 + x + x2)(x + 1) = 0

Reorder the terms:
(-1 + x + x2)(1 + x) = 0

Multiply (-1 + x + x2) * (1 + x)
(-1(1 + x) + x(1 + x) + x2(1 + x)) = 0
((1 * -1 + x * -1) + x(1 + x) + x2(1 + x)) = 0
((-1 + -1x) + x(1 + x) + x2(1 + x)) = 0
(-1 + -1x + (1 * x + x * x) + x2(1 + x)) = 0
(-1 + -1x + (1x + x2) + x2(1 + x)) = 0
(-1 + -1x + 1x + x2 + (1 * x2 + x * x2)) = 0
(-1 + -1x + 1x + x2 + (1x2 + x3)) = 0

Combine like terms: -1x + 1x = 0
(-1 + 0 + x2 + 1x2 + x3) = 0
(-1 + x2 + 1x2 + x3) = 0

Combine like terms: x2 + 1x2 = 2x2
(-1 + 2x2 + x3) = 0

Solving
-1 + 2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.